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ํŒŒ์ด์ฌ := ์—ฐ์‚ฐ์ž์™€ dict()์— ๋Œ€ํ•ด์„œ

by beomcoder 2023. 2. 15.
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ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค๋ฅผ ํ’€๊ณ  ์žˆ์—ˆ๋Š”๋ฐ ์ƒ์†Œํ•œ ์—ฐ์‚ฐ์ž๊ฐ€ ์žˆ์–ด์„œ ์•Œ๋ ค์ฃผ๋ ค๊ณ  ํ•œ๋‹ค.

:= ๋ผ๋Š” ์—ฐ์‚ฐ์ž์ธ๋ฐ ํŒŒ์ด์ฌ 3.8๋ถ€ํ„ฐ ์‚ฌ์šฉํ•  ์ˆ˜ ์žˆ๋‹ค.

## 1๋ฒˆ ์ฝ”๋“œ -> ์ผ๋ฐ˜ ์ฝ”๋“œ
s='walrus eat kimchi' ## s์— ๋ฌธ์ž์—ด์„ ํ• ๋‹น
result = 'walrus' in s ## 'walrus' in s๋ฅผ result์— ํ• ๋‹น
if result: ## result๊ฐ€ True๋ผ๋ฉด
    print(s) ## s ์ถœ๋ ฅ
    print(result) ## result ์ถœ๋ ฅ
 
 
## 2๋ฒˆ ์ฝ”๋“œ -> := ์‚ฌ์šฉ
## s์— ๋ฌธ์ž์—ด์„ ํ• ๋‹นํ•˜๊ณ , 'walrus' in s๋ฅผ result์— ํ• ๋‹นํ•˜๊ณ , result๊ฐ€ True ๋ผ๋ฉด
if result := 'walrus' in (s := 'walrus eat kimchi'):
    print(s)  ## s ์ถœ๋ ฅ
    print(result) ## result ์ถœ๋ ฅ

 

๊ทธ๋ฆฌ๊ณ  dict()์— ๋Œ€ํ•ด ์•Œ์•˜๋‹ค. ๋‚˜๋Š” ์•„๋ž˜์˜ ํ‘œ์—์„œ db๋ฅผ 0๋ฒˆ์งธ ์ธ๋ฑ์Šค๋ฅผ key,

1๋ฒˆ์งธ ์ธ๋ฑ์Šค๋ฅผ value๋กœ ๋งŒ๋“ค๊ธฐ ์œ„ํ•ด์„œ ๋”•์…”๋„ˆ๋ฆฌ๋‚ดํฌ๊ตฌ๋ฌธ์œผ๋กœ ํ•ด๊ฒฐํ–ˆ๋‹ค.

 

def solution(id_pw, db):
    db = {info[0]:info[1] for info in db}
    if id_pw[0] in db.keys():
        if id_pw[1] == db[id_pw[0]]:
            return 'login'
        else:
            return 'wrong pw'
    else:
        return 'fail'

 

ํ•˜์ง€๋งŒ dict()๋ฅผ ์“ฐ๋ฉด ์•Œ์•„์„œ key, value๋กœ ๋‚˜๋ˆ ์ค€๋‹ค๋Š” ๊ฒƒ์ด๋‹ค.

 

def solution(id_pw, db):
    # db = {info[0]:info[1] for info in db}
    db = dict(db)
    print(db)
    # if id_pw[0] in db.keys():
    #     if id_pw[1] == db[id_pw[0]]:
    #         return 'login'
    #     else:
    #         return 'wrong pw'
    # else:
    #     return 'fail'

 

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